Two *template-id*s refer to the same
class, function, or variable if

- their
*template-name*s,*operator-function-id*s, or*literal-operator-id*s refer to the same template and - their corresponding type
*template-argument*s are the same type and - their corresponding non-type
*template-argument*s of pointer-to-member type refer to the same class member or are both the null member pointer value and - their corresponding non-type
*template-argument*s of reference type refer to the same object or function and - their remaining corresponding
non-type
*template-argument*s have the same type and value after conversion to the type of the*template-parameter*, where they are considered to have the same value if they compare equal with the == operator ([expr.eq]), and - their corresponding template
*template-argument*s refer to the same template.

[ Example

: *end example*

]template<class E, int size> class buffer { /* ... */ }; buffer<char,2*512> x; buffer<char,1024> y;declares x and y to be of the same type, and

template<class T, void(*err_fct)()> class list { /* ... */ }; list<int,&error_handler1> x1; list<int,&error_handler2> x2; list<int,&error_handler2> x3; list<char,&error_handler2> x4;declares x2 and x3 to be of the same type. Their type differs from the types of x1 and x4.

template<class T> struct X { }; template<class> struct Y { }; template<class T> using Z = Y<T>; X<Y<int> > y; X<Z<int> > z;declares y and z to be of the same type. —

Two such *decltype-specifier*s
refer to the same type only if their *expression*s are
equivalent ([temp.over.link]).